Hopefully final draft
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@@ -91,7 +91,7 @@ independent of the bandwidth.
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Silverman's rule on $\mathcal{B}_1 = \{0,b\}$ ($|\mathcal{B}_1|=2$,
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$\hat\sigma_1 = b/2$) gives $h_1 = \kappa b$ with $\kappa := 1.06 \cdot 2^{-1/5}/2$, i.e.\
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$v_1 = 1/(\kappa b)$ — the bandwidth scales linearly with $b$.
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$v_1 = 1/(\kappa b)$: the bandwidth scales linearly with $b$.
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\paragraph{True adaptive loss.} Substituting $v_1 = 1/(\kappa b)$,
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\[
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